3x+7=4x^2

Solution for 3x+7=4x^2 equation:

3x+7=4x^2

We move all terms to the left:

3x+7-(4x^2)=0

determiningTheFunctionDomain
-4x^2+3x+7=0

a = -4; b = 3; c = +7;
Δ = b2-4ac
Δ = 32-4·(-4)·7
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-11}{2*-4}=\frac{-14}{-8}
=1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+11}{2*-4}=\frac{8}{-8}
=-1
$